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switch(pin){
case 0:
break;
case 1:
ADMUX = 1;
case 2:
ADMUX = 1 << 1;
case 3:
ADMUX = 1 | 1 << 1;
case 4:
ADMUX = 1 << 2;
case 5:
ADMUX = 1 | 1 << 2;
case 6:
ADMUX = 1 << 1 | 1 << 2;
}
ADMUX = (pin == 0 ? 0 : 6)
// UPD: ну кагбэ absolut сказал точнее 🙂
Эквивалентный код в данном случае:
if( 0 < pin && pin < 7 ) ADMUX = 6;
1 << 1 == 2 == pin
1 | 1 << 1 == 3 == pin и тд. )