"PHP" / Говнокод #557 Ссылка на оригинал

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if ($ajax_teamID == $value['team2ID']){
              $visitors_team = $Bet->CBetType[$Bet->betTypeIndex]->CTeam->getOne($value['team2ID'])->title;
              $home_team     = $Bet->CBetType[$Bet->betTypeIndex]->CTeam->getOne($value['team1ID'])->title;
        } else {      
              $home_team     = $Bet->CBetType[$Bet->betTypeIndex]->CTeam->getOne($value['team1ID'])->title;              
              $visitors_team = $Bet->CBetType[$Bet->betTypeIndex]->CTeam->getOne($value['team2ID'])->title;
        }

Не делайте так.

Запостил: guest guest, (Updated )

Комментарии (6) RSS

  • Индивидуум:
    Тогда приведите пример, как правильней…
    Ответить
  • 27:
    <?php
    $i = ($ajax_teamID==$value['team2ID']) ? 1 : 0;
    $visitors_team = $Bet->CBetType[$Bet->betTypeIndex]->CTeam->getOne($value['team'+1+$i+'ID'])->title;
    	$home_team = $Bet->CBetType[$Bet->betTypeIndex]->CTeam->getOne($value['team'+1+1-$i+'ID'])->title;
    ?>
    Ответить
  • 27:
    <?php
    $i = ($ajax_teamID==$value['team2ID']) ? 1 : 0;
    $visitors_team = $Bet->CBetType[$Bet->betTypeIndex]->CTeam->getOne($value['team'+1+$i+'ID'])->title;
        $home_team = $Bet->CBetType[$Bet->betTypeIndex]->CTeam->getOne($value['team'+2-$i+'ID'])->title;
    ?>
    Ответить
  • 27:
    вотак
    <?php
    $i = ($ajax_teamID==$value['team2ID']) ? 2 : 1;
    $visitors_team = $Bet->CBetType[$Bet->betTypeIndex]->CTeam->getOne($value['team'+$i+'ID'])->title;
        $home_team = $Bet->CBetType[$Bet->betTypeIndex]->CTeam->getOne($value['team'+3-$i+'ID'])->title;
    ?>
    Ответить
  • Иван:
    27, правильное решение такое
    <?
    $home_team     = $Bet->CBetType[$Bet->betTypeIndex]->CTeam->getOne($value['team1ID'])->title;              
    $visitors_team = $Bet->CBetType[$Bet->betTypeIndex]->CTeam->getOne($value['team2ID'])->title;
    ?>
    Ответить

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Семь раз отмерь — один отрежь, guest!

    А не использовать ли нам bbcode?


    8